- 9 лет ago
- Published в: Irish open golf 2022 betting
- 0
- Автор: Kazrakree
With only 4 intermediate cities, you enumerate all 24 permutations. For each permutation use your shortest two-point algorithm to compute the path from head to tail, and its total distance. Then given the start and ending point, there are 12 possibilities attaching to one of abcd and for each two possibilities for the interior.
You've computed these distances already, so you add on the distance from S to the head and the tail to E. Choose minimum. So once you've precomputed the intermediate distances for a fixed set of interior cities you need to do 12 two point shortest path problems for any pair of start and end points.
This obviously scales poorly with increasing number of intermediate cities. It's not clear to me that it could do better unless you impose greater restrictions on the graph structure is this in a physical Euclidenan space? Triangle inequality? My thought example: suppose all intermediate distances between cities are O 1. Drag a point or path to adjust it, or click on a point to remove it.
Google Maps displays the total distance in miles on top of the path. It is also displayed in a card at the bottom of the map. You can remove the paths by clicking on the cross on the card. The process is only slightly different. Let's see how it works on Google Maps for iOS. Open the Google Maps app. Locate the first spot and touch to mark it with a red pin.
At the bottom of the map, tap the name of the place. In the pop-up menu, choose Measure distance. Drag the map so that the black circle, or crosshairs, is on the next point you want to add. You can keep adding multiple points.
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